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2.Motion in Straight Line
medium
A lift is going up. The total mass of the lift and the passenger is $1500\, kg$. The variation in the speed of the lift is as given in the graph. the height to which the lift takes the passenger is ............ $m$

A
$3.6$
B
$8$
C
$1.8$
D
$36$
Solution
(d)Distance travelled by the lift $ = $ Area under velocity time graph
$ = \left( {\frac{1}{2} \times 2 \times 3.6} \right) + \left( {8 \times 3.6} \right) + \left( {\frac{1}{2} \times 2 \times 3.6} \right)$= $36m$
Standard 11
Physics