Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
medium

A liquid of mass m and specific heat $c$ is heated to a temperature $2T.$ Another liquid of mass $m/2$ and specific heat $2c$ is heated to a temperature $T.$ If these two liquids are mixed, the resulting temperature of the mixture is

A

$(2/3)T$

B

$(8/5)T$

C

$(3/5)T$

D

$(3/2)T$

Solution

(d) Temperature of mixture

${\theta _{mix}} = \frac{{{m_1}{c_1}{\theta _1} + {m_2}{c_2}{\theta _2}}}{{{m_1}{c_1} + {m_2}{c_2}}} = \frac{{m \times c \times 2T + \frac{m}{2}(2c)T}}{{m.c + \frac{m}{2}(2c)}} = \frac{3}{2}T$

Standard 11
Physics

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