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10-1.Thermometry, Thermal Expansion and Calorimetry
medium
A liquid of mass m and specific heat $c$ is heated to a temperature $2T.$ Another liquid of mass $m/2$ and specific heat $2c$ is heated to a temperature $T.$ If these two liquids are mixed, the resulting temperature of the mixture is
A
$(2/3)T$
B
$(8/5)T$
C
$(3/5)T$
D
$(3/2)T$
Solution
(d) Temperature of mixture
${\theta _{mix}} = \frac{{{m_1}{c_1}{\theta _1} + {m_2}{c_2}{\theta _2}}}{{{m_1}{c_1} + {m_2}{c_2}}} = \frac{{m \times c \times 2T + \frac{m}{2}(2c)T}}{{m.c + \frac{m}{2}(2c)}} = \frac{3}{2}T$
Standard 11
Physics