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1. Electric Charges and Fields
hard
A long cylindrical volume contains a uniformly distributed charge of density $\rho \;Cm ^{-3}$. The electric field inside the cylindrical volume at a distance $x =\frac{2 \varepsilon_{0}}{\rho} m$ from its axis is $.......Vm ^{-1}$

A
$2$
B
$1$
C
$0$
D
$3$
(JEE MAIN-2022)
Solution

$\int Eds \cos 0=\frac{ q }{\varepsilon_{0}}$
$\Rightarrow E \cdot 2 \pi \times xh =\frac{\rho \times \pi x ^{2} h }{\varepsilon_{0}}$
$\Rightarrow E =\frac{\rho x }{2 \varepsilon_{0}}$
$\Rightarrow E =\frac{\rho}{2 \varepsilon_{0}} \times \frac{2 \varepsilon_{0}}{\rho}=1$
Standard 12
Physics
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