A man draws a card from a pack of 52 playing | vedclass

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Question

(c) The required probability is given by

$= \frac{{{}^{39}{C_1}}}{{{}^{52}{C_1}}} 	imes \frac{{{}^{39}{C_1}}}{{{}^{52}{C_1}}} 	imes \frac{{{}^{13

Vedclass · Accepted Answer

$\frac{9}{{64}}$

Vedclass · Answer

(c) The required probability is given by

$= \frac{{{}^{39}{C_1}}}{{{}^{52}{C_1}}} 	imes \frac{{{}^{39}{C_1}}}{{{}^{52}{C_1}}} 	imes \frac{{{}^{13}{C_1}}}{{{}^{52}{C_1}}} $

$= \frac{3}{4} 	imes \frac{3}{4} 	imes \frac{1}{4} = \frac{9}{{64}}.$

A man draws a card from a pack of $52$ playing cards, replaces it and shuffles the pack. He continues this processes until he gets a card of spade. The probability that he will fail the first two times is

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