A man of mass m₁ is standing on a platform of mass m₂ kept on a smooth horizontal sur

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4-1.Newton's Laws of Motion

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A man of mass $m_1$ is standing on a platform of mass $m_2$ kept on a smooth horizontal surface. If the man starts moving on the platform with a velocity $v$ relative to the platform, then recoil velocity of platform is

A

$\frac{m_2v}{m_1+m_2}$

B

$\frac{m_1v}{m_1+m_2}$

C

$\frac{(m_1 + m_2)v}{m_1}$

D

$\frac{(m_1 + m_2)v}{m_2}$

Solution

$\mathrm{p}_{\mathrm{i}}=\mathrm{p}_{\mathrm{f}}$

$o=\mathrm{m}_{1}\left(\mathrm{v}-\mathrm{v}^{\prime}\right)-\mathrm{m}_{2} \mathrm{v}^{\prime}$

$\mathrm{v}^{\prime}=\frac{\mathrm{m}_{1} \mathrm{v}}{\mathrm{m}_{1}+\mathrm{m}_{2}}$

Standard 11

Physics

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