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4-1.Newton's Laws of Motion
normal
System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass $2\,m$ and $m$ just after the string is cut will be
A$\frac {g}{2}$ upwards, $g$ downwards
B$g$ upwards, $\frac {g}{2}$ downwards
C$g$ upwards, $2g$ downwards
D$2g$ upwards, $g$ downwards
Solution
$\mathrm{Kx}=3 \mathrm{mg}$
after cut the string
$a=\frac{F_{\text {ret }}}{2 m}=\frac{k x-2 m g}{2 m}$
$a=\frac{3 m g-2 m g}{2 m}=\frac{g}{2}$
after cut the string
$a=\frac{F_{\text {ret }}}{2 m}=\frac{k x-2 m g}{2 m}$
$a=\frac{3 m g-2 m g}{2 m}=\frac{g}{2}$
Standard 11
Physics
