A manometer connected to a closed tap reads 4.5×10^5, pascal . When tap is opened reading of manome

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9-1.Fluid Mechanics

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A manometer connected to a closed tap reads $4.5\times10^5\, pascal$. When the tap is opened the reading of the manometer falls to $4\times10^5\, pascal$. Then the velocity of flow of water is ........ $ms^{-1}$

A

$7$

B

$8$

C

$9$

D

$10$

Solution

$\frac{P_{1}-P_{2}}{\rho g}=\frac{v^{2}}{2 g} \Rightarrow \frac{4.5 \times 10^{5}-4 \times 10^{5}}{10^{3} \times g}=\frac{v^{2}}{2 g}$

$\therefore \mathrm{v}=10 \mathrm{m} / \mathrm{s}$

Standard 11

Physics

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