A metal rod of silver at 0°C is heated to 100°C . It's length is increased by 0.19, cm .

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A metal rod of silver at $0°C$ is heated to $100°C$. It's length is increased by $0.19\, cm$. Coefficient of cubical expansion of the silver rod is

A

$5.7 \times 10^{-5}{°C^{-1}}$

B

$0.63 \times 10^{-5} {°C^{-1}}$

C

$1.9 \times 10^{-5}{°C^{-1}}$

D

$16.1 \times 10^{-5} {°C^{-1}}$

Solution

(a) $\alpha = \frac{{\Delta L}}{{{L_0}(\Delta \theta )}}$$ = \frac{{0.19}}{{100\,(100 – 0)}} = 1.9 \times {10^{ – 5}}{°C^{-1}}$

Now $\gamma = 3\alpha = 3 \times 1.9 \times 10^{-5}/°C = 5.7 \times 10^{-5}{°C^{-1}}$

Standard 11

Physics

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