Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
normal

If there are no heat losses, the heat released by the condensation of $x$ gm of steam at $100^o C$ into water at $100^o C$ can be used to convert $y$ gm of ice at $0^o C$ into water at $100^o C$. Then the ratio $y : x$ is nearly

A

$1:1$

B

$2.5 : 1$

C

$2:1$

D

$3:1$

Solution

(d) Heat released to convert $x$ gm of steam at $100°C$ to water at $100°C$ is $x \times 540 \,cals.$

If y gm of ice is converted from $0°C$ to water at $100°C$ it requires heat $y \times 80 + y \times 1 \times 100 = 180 y$

$\therefore x \times 540 = 180\,y$ or $\frac{y}{x} = \frac{{540}}{{180}} = \frac{3}{1}$

Standard 11
Physics

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