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1.Units, Dimensions and Measurement
easy
A metal wire has mass $(0.4 \pm 0.002)\,g$, radius $(0.3 \pm 0.001)\,mm$ and length $(5 \pm 0.02) \,cm$. The maximum possible percentage error in the measurement of density will nearly be $.......\%$
A
$1.4$
B
$1.2$
C
$1.3$
D
$1.6$
(NEET-2023)
Solution
$\rho=\frac{ M }{ V }$
$\rho =\frac{ M }{\pi r ^2 \ell}$
$\frac{\Delta \rho}{\rho} =\frac{\Delta M }{ M }+\frac{2 \Delta r }{ r }+\frac{\Delta l}{l}$
$\frac{\Delta \rho}{\rho} \%$ $=\left[\frac{0.002}{0.4}+\frac{2(0.001)}{(0.3)}+\frac{0.02}{5}\right] \times 100 \%$
$=\frac{1}{2} \%+\frac{2}{3} \%+\frac{2}{5} \%$
$=1.6 \%$
Standard 11
Physics
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