10-2.Transmission of Heat
medium

A metallic sphere cools from $50^{\circ} C$ to $40^{\circ} C$ in $300 \,s.$ If atmospheric temperature around is $20^{\circ} C ,$ then the sphere's temperature after the next $5$ minutes will be close to$.....C$

A

$33$

B

$35$

C

$31$

D

$28$

(JEE MAIN-2020)

Solution

$\frac{50-40}{300}=\beta\left(\frac{50+40}{2}-20\right)$

$\frac{40-T}{300}=\beta\left(\frac{40+T}{2}-20\right)$

$\therefore \quad T=\frac{100}{3}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.