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10-2.Transmission of Heat
medium
A metallic sphere cools from $50^{\circ} C$ to $40^{\circ} C$ in $300 \,s.$ If atmospheric temperature around is $20^{\circ} C ,$ then the sphere's temperature after the next $5$ minutes will be close to$.....C$
A
$33$
B
$35$
C
$31$
D
$28$
(JEE MAIN-2020)
Solution
$\frac{50-40}{300}=\beta\left(\frac{50+40}{2}-20\right)$
$\frac{40-T}{300}=\beta\left(\frac{40+T}{2}-20\right)$
$\therefore \quad T=\frac{100}{3}$
Standard 11
Physics