A motor car moving with a uniform speed of $20\,m/\sec $ comes to stop on the application of brakes after travelling a distance of $10\,m$ Its acceleration is..........$m/{\sec ^2}$
A motor car moving with a uniform speed of $20\,m/\sec $ comes to stop on the application of brakes after travelling a distance of $10\,m$ Its acceleration is..........$m/{\sec ^2}$
- A
$20$
- B
$ - 20$
- C
$ - 40$
- D
$ + 2$
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Acceleration-time graph of a body is shown. The corresponding velocity-time graph of the same body is
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If the velocity of a particle is given by $v = {(180 - 16x)^{1/2}} m/s$, then its acceleration will be.......$ms^{-2}$
If the velocity of a particle is given by $v = {(180 - 16x)^{1/2}} m/s$, then its acceleration will be.......$ms^{-2}$
Given below are two statements:
Statement $I:$ Area under velocity- time graph gives the distance travelled by the body in a given time.
Statement $II:$ Area under acceleration- time graph is equal to the change in velocity- in the given time.
In the light of given statements, choose the correct answer from the options given below.
Given below are two statements:
Statement $I:$ Area under velocity- time graph gives the distance travelled by the body in a given time.
Statement $II:$ Area under acceleration- time graph is equal to the change in velocity- in the given time.
In the light of given statements, choose the correct answer from the options given below.
- [JEE MAIN 2023]
The motion of a body is given by the equation $\frac{{dv(t)}}{{dt}} = 6.0 - 3v(t)$. where $v(t)$ is speed in $m/s$ and $t$ in $\sec $. If body was at rest at $t = 0$
The motion of a body is given by the equation $\frac{{dv(t)}}{{dt}} = 6.0 - 3v(t)$. where $v(t)$ is speed in $m/s$ and $t$ in $\sec $. If body was at rest at $t = 0$
- [IIT 1995]