Velocity of bullet becomes one third after it penetrates 4,cm in a wooden block. Assuming that bulle

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2.Motion in Straight Line

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The velocity of the bullet becomes one third after it penetrates $4\,cm$ in a wooden block. Assuming that bullet is facing a constant resistance during its motion in the block. The bullet stops completely after travelling at $(4+x)\,cm$ inside the block. The value of $x$ is$.....$

A$2$

B$1$

C$0.5$

D$1.5$

(JEE MAIN-2022)

Solution

$\left(\frac{ V }{3}\right)^{2} = V ^{2}-2 a (4) \Rightarrow a =\frac{8 V ^{2}}{9(8)}=\frac{ V ^{2}}{9}$
$0= V ^{2}-2 a (4+ x )$
$V ^{2} =2\left(\frac{ V ^{2}}{9}\right)(4+ x )$
$4.5 =4+ x$
$x =0.5$

Standard 11

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Solution

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