A network of four capacitors of capacity equa | vedclass

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Question

$\mathrm{Q}_{4}=4 \mathrm{CV}$

$\mathrm{Q}_{2}=\left(\frac{6}{11} \mathrm{C}\right) \mathrm{V}=\frac{6 \mathrm{CV}}{11} $

$\Rightarrow \frac{\ma

Vedclass · Accepted Answer

$\frac{3}{22}$

Vedclass · Answer

$\mathrm{Q}_{4}=4 \mathrm{CV}$

$\mathrm{Q}_{2}=\left(\frac{6}{11} \mathrm{C}ight) \mathrm{V}=\frac{6 \mathrm{CV}}{11} $

$\Rightarrow \frac{\mathrm{Q}_{2}}{\mathrm{Q}_{4}}=\frac{6 \mathrm{CV}}{11} 	imes \frac{1}{4 \mathrm{CV}}=\frac{3}{22}$

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