Gujarati
Hindi
1. Electric Charges and Fields
normal

Electric field at a place is $\overrightarrow E  = {E_0}\widehat i\,\,V/m$. A particle of charge $+q_0$ moves from point $A$  to $B$ along a circular path find work done in this motion by electric field :-

A

$\sqrt 2 {q_0}a{E_0}$

B

$\frac{{{q_0}a{E_0}}}{{\sqrt 2 }}$

C

${{q_0}a{E_0}}$

D

${2q{E_0}a}$

Solution

$\mathrm{w}=\overrightarrow{\mathrm{F}} \cdot \overrightarrow{\mathrm{d}}$

$=\mathrm{q}_{0} \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d}}$

$=\mathrm{q}_{0}\left(\mathrm{E}_{0} \hat{\mathrm{i}}\right) \cdot(\mathrm{a} \hat{\mathrm{i}}-\mathrm{a} \hat{\mathrm{j}})$

$=\mathrm{q}_{0} \mathrm{E}_{0} \mathrm{a}$

Standard 12
Physics

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