A nucleus ruptures into two nuclear parts whi | vedclass

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Question

Conserving momentum, $m_1 v_1=m_2 v_2$

$\frac{2}{1}=\frac{v_1}{v_2}=\frac{m_2}{m_1}$

$\Rightarrow \frac{m_2}{m_1}=\frac{2}{1}=\frac{\rho \cdot \

Vedclass · Accepted Answer

$1:{2^{1/3}}$

Vedclass · Answer

Conserving momentum, $m_1 v_1=m_2 v_2$

$\frac{2}{1}=\frac{v_1}{v_2}=\frac{m_2}{m_1}$

$\Rightarrow \frac{m_2}{m_1}=\frac{2}{1}=\frac{\rho \cdot \frac{4}{3} \pi r_2^3}{\rho \cdot \frac{4}{3} \pi r_1^3}$

$\Rightarrow \frac{r_2}{r_1}=2^{\frac{1}{3}}$

$r_1: r_2=1: 2^{\frac{1}{3}}$

A nucleus ruptures into two nuclear parts which have their velocity ratio equal to $2 : 1$. What will be the ratio of their nuclear size (nuclear radius)

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