A parallel plate capacitor after charging is kept connected to a battery and plates are pulled apart

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2. Electric Potential and Capacitance

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A parallel plate capacitor after charging is kept connected to a battery and the plates are pulled apart with the help of insulating handles. Now which of the following quantities will decrease?

A

Charge

B

Capacitance

C

Energy stored

D

All of these

Solution

(d)

$V$ remains constant

$C=\frac{A \varepsilon_0}{d} \Rightarrow d$ increases

$C$ decreases

$q=C V$

$q$ decreases $U=\frac{1}{2} C V^2$

$U$ decreases

Standard 12

Physics

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