Gujarati
2. Electric Potential and Capacitance
easy

A $700\,pF$ capacitor is charged by a $50\,V$ battery. The electrostatic energy stored by it is

A

$17.0 \times {10^{ - 8}}\,J$

B

$13.6 \times {10^{ - 9}}\,J$

C

$9.5 \times {10^{ - 9}}\,J$

D

$8.7 \times {10^{ - 7}}\,J$

Solution

(d) $U = \frac{1}{2}C{V^2} = \frac{1}{2} \times 700 \times {10^{ – 12}}{(50)^2}$$ = 8.7 \times {10^{ – 7}}\,J$

Standard 12
Physics

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