Gujarati
Hindi
2. Electric Potential and Capacitance
medium

A parallel plate capacitor is charged fully by using a battery. Then, without disconnecting the battery, the plates are moved further apart. Then,

A

the charge on the capacitor increases

B

the voltage difference between the plates decreases

C

the capacitance increases

D

the electrostatic energy stored in the capacitor decreases

(KVPY-2009)

Solution

(d)

As plates are moved far away further, capacity of capacitor $\left(C=\frac{\varepsilon_0 A}{d}\right)$ decreases.

As battery remains connected during this activity, potential difference between plates remains same.

So, the charge on plates $(Q=C V)$ decreases.

Also, energy of capacitor $\left(U=\frac{1}{2} C V^2\right)$ decreases as capacitance decreases. So, correct option is $( d )$.

Standard 12
Physics

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