A fully charged capacitor has a capacitance $‘C’$. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $‘s’$ and mass $‘m’$. If the temperature of the block is raised by ‘$\Delta T$’, the potential difference $‘V’$ across the capacitance is
$\frac{{ms\Delta T}}{C}$
$\sqrt {\frac{{2ms\Delta T}}{C}} $
$\sqrt {\frac{{2mC\Delta T}}{s}} $
$\frac{{mC\Delta T}}{s}$
A parallel plate capacitor after charging is kept connected to a battery and the plates are pulled apart with the help of insulating handles. Now which of the following quantities will decrease?
The energy density $u$ is plotted against the distance $r$ from the centre of a spherical charge distribution on a $log$-$log$ scale. The slope of obtianed straight line is :
If $E$ is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to
A capacitor is charged to $200\, volt$ it has $0.1$ coulomb charge. When it is discharged, energy will be.....$J$
A capacitor of capacitance $C$ is charged with the help of a $200 \,V$ battery. It is then discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity $2.5 \times 10^2 \,J / kg$ and mass $0.1 \,kg$. If the temperature of the block rises by $0.4 \,K$, the value of $C$ is