A parallel plate capacitor is to be designed with a voltage rating $1\; k\,V ,$ using a material of dielectric constant $3$ and dielectric strength about $10^{7}\; V\,m ^{-1} .$ (Dielectric strength is the maximum electric field a material can tolerate without breakdown, i.e., without starting to conduct electricity through partial ionisation.) For safety, we should like the field never to exceed, say $10 \%$ of the dielectric strength. What minimum area (in $cm^2$) of the plates is required to have a capacitance of $50\; pF ?$
Potential rating of a parallel plate capacitor, $V =1 \,kV =1000 \,V$
Dielectric constant of a material, $\varepsilon_{r}=3$
Dielectric strength $=10^{7} \,V / m$
For safety, the field intensity never exceeds $10 \%$ of the dielectric strength.
Hence, electric field intensity, $E=10 \%$ of $10^{7}=10^{6}\, V / m$
Capacitance of the parallel plate capacitor, $C =50 \,pF =50 \times 10^{-12}\, F$
Distance between the plates is given by, $d=\frac{V}{E}$
$=\frac{1000}{10^{6}}=10^{-3} \,m$
Capacitance is given by the relation, $C=\frac{\epsilon_{0} \epsilon_{,} A}{d}$
Where,
$A=$ Area of each plate
$\epsilon_{0}=$ Permittivity of free space $=8.85 \times 10^{-12} \,N ^{-1} \,C ^{2} \,m ^{-2}$
$\therefore A =\frac{C d}{\epsilon_{0} \in}$
$=\frac{50 \times 10^{-12} \times 10^{-3}}{8.85 \times 10^{-12} \times 3} \approx 19 \,cm ^{2}$
Hence, the area of each plate is about $19\; cm ^{2}$.
A spherical capacitor has an inner sphere of radius $12 \;cm$ and an outer sphere of radius $13\; cm .$ The outer sphere is earthed and the inner sphere is given a charge of $2.5\; \mu \,C .$ The space between the concentric spheres is filled with a liquid of dielectric constant $32$
$(a)$ Determine the capacitance of the capacitor.
$(b)$ What is the potential of the inner sphere?
$(c)$ Compare the capacitance of this capacitor with that of an isolated sphere of radius $12 \;cm .$ Explain why the latter is much smaller.
Between the plates of a parallel plate condenser, a plate of thickness ${t_1}$ and dielectric constant ${k_1}$ is placed. In the rest of the space, there is another plate of thickness ${t_2}$ and dielectric constant ${k_2}$. The potential difference across the condenser will be
If the dielectric constant and dielectric strength be denoted by $k$ and $x$ respectively, then a material suitable for use as a dielectric in a capacitor must have
A parallel plate capacitor is first charged and then a dielectric slab is introduced between the plates. The quantity that remains unchanged is
The radii of the inner and outer spheres of a condenser are $9\,cm$ and $10\,cm$ respectively. If the dielectric constant of the medium between the two spheres is $6$ and charge on the inner sphere is $18 \times {10^{ - 9}}\;coulomb$, then the potential of inner sphere will be, if the outer sphere is earthed........$volts$