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2. Electric Potential and Capacitance
easy
A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is $A\;metr{e^2}$ and the separation is $t$ $metre$. The dielectric constants are ${k_1}$ and ${k_2}$ respectively. Its capacitance in farad will be
A
$\frac{{{\varepsilon _0}A}}{t}({k_1} + {k_2})$
B
$\frac{{{\varepsilon _0}A}}{t}.\frac{{{k_1} + {k_2}}}{2}$
C
$\frac{{2{\varepsilon _0}A}}{t}({k_1} + {k_2})$
D
$\frac{{{\varepsilon _0}A}}{t}.\frac{{{k_1} - {k_2}}}{2}$
(AIIMS-2001)
Solution
(b) The two capacitors are in parallel so $C = \frac{{{\varepsilon _0}A}}{{t \times 2}}({k_1} + {k_2})$
Standard 12
Physics
