A particle covers 50, m distance when projected with an initial speed. On same surface it will cover

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3-2.Motion in Plane

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A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$

A

$100$

B

$150 $

C

$200 $

D

$250 $

Solution

(c) $R = \frac{{{u^2}\sin 2\theta }}{g} = R \propto {u^2}.$ So if the speed of projection doubled, the range will becomes four times,

i.e., $4 \times 50 = 200\,m$

Standard 11

Physics

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