Gujarati
3-2.Motion in Plane
normal

A particle does uniform circular motion in a horizontal plane. The radius of the circle is $20$ cm. The centripetal force acting on the particle is $10\, N$. It's kinetic energy is ........ $J$

A

$0.1 $

B

$0.2$

C

$2.0 $

D

$1.0$

Solution

(d) $\frac{{m{v^2}}}{r} = 10$ ==> $\frac{1}{2}m{v^2} = 10 \times \frac{r}{2} = 1\,J$

Standard 11
Physics

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