Average velocity of a particle is projectile | vedclass

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Question

Displacement $=\sqrt{\left(\frac{R}{2}ight)^{2}+H^{2}}$

$R=\frac{u^{2} \sin 2 	heta}{g}$

$H=\frac{u^{2} \sin ^{2} 	heta}{g}$

$t=\frac{T}{

Vedclass · Accepted Answer

$\frac{u}{2}\sqrt {1 + 3{{\cos }^2}	heta } $

Vedclass · Answer

Displacement $=\sqrt{\left(\frac{R}{2}ight)^{2}+H^{2}}$

$R=\frac{u^{2} \sin 2 	heta}{g}$

$H=\frac{u^{2} \sin ^{2} 	heta}{g}$

$t=\frac{T}{2}=\frac{u \sin 	heta}{g}$

$\left|V_{a v g}ight|=\frac{| 	ext {displacement} |}{t}=\frac{u^{2} \sin 	heta}{g} \sqrt{4 \cos ^{2} 	heta+\sin ^{2} 	heta} \sqrt{\frac{1}{4}} \frac{1}{\frac{u \sin 	heta}{g}}$

$=\frac{u}{2} \sqrt{1+3 \cos ^{2} 	heta}$

Average velocity of a particle is projectile motion between its starting point and the highest point of its trajectory is : (projection speed = $u$, angle of projection from horizontal= $\theta$)

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