3-2.Motion in Plane
normal

એક કણનો પ્રારંભિક વેગ $(3\hat i + 4\hat j$$ ) $ અને પ્રવેગ $(0.4\hat i + 0.3\hat j$ $)$ છે.તે કણની $ 10 s $ પછી ઝડપ ______ હશે.

A

$7 $ એકમ

B

$7$ $\sqrt 2 $ એકમ

C

$8.5$  એકમ

D

$10 $ એકમ

Solution

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\\
Initial\,velocity,\,\overline u  = 3\hat i + 4\hat j\\
Acceleration,\,\overline a  = 0.4\hat i + 0.3\hat j\\
Time\,,\,t = 10\,s\\
Let\,\overline v \,be\,velocity\,of\,a\,particle\,\\
after\,10\,s.
\end{array}$

$\begin{array}{l}
{\rm{Using,}}\,\overline v \, = \overline u  + \,\overline a t\\
\therefore \,\,\,\overline v  = \left( {3\hat i + 4\hat j} \right) + \left( {0.4\hat i + 0.3\hat j} \right)\left( {10} \right)\\
\,\,\,\,\,\,\,\,\, = \,3\hat i + 4\hat j + 4\hat i + 3\hat j = 7\hat i + 7\hat j\\
Speed\,of\,the\,particle\,after\,10\,s = \left| {\overline v } \right|\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt {{{\left( 7 \right)}^2} + {{\left( 7 \right)}^2}}  = 7\sqrt 2 \,units
\end{array}$

 

Standard 11
Physics

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