A truck travelling due north at $20 \,m/s $ turns west and travels at the same speed. The change in its velocity be
$40\, m/s \,N-W$
$20\sqrt 2 \, m/s\, N-W$
$40\, m/s\, S-W$
$20\sqrt 2 \,m/s \,S-W$
Which of the four arrangements in the figure correctly shows the vector addition of two forces $\overrightarrow {{F_1}} $ and $\overrightarrow {{F_2}} $ to yield the third force $\overrightarrow {{F_3}} $
A particle has displacement of $12 \,m$ towards east and $5 \,m$ towards north then $6 \,m $ vertically upward. The sum of these displacements is........$m$
What vector must be added to the two vectors $\hat i - 2\hat j + 2\hat k$ and $2\hat i + \hat j - \hat k,$ so that the resultant may be a unit vector along $X-$axis
The resultant of $\overrightarrow A + \overrightarrow B $ is ${\overrightarrow R _1}.$ On reversing the vector $\overrightarrow {B,} $ the resultant becomes ${\overrightarrow R _2}.$ What is the value of $R_1^2 + R_2^2$
Two forces acting on point $A$ along their side and having magnitude reciprocal to length of side then resultant of these forces will be proportional to