A particle is moving along a straight line with constant acceleration. At end of tenth se

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2.Motion in Straight Line

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A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes $20\, m/s$ and in tenth second it travels a distance of $10\, m$. Then the acceleration of the particle will be........$m/s^2$

A

$10$

B

$20$

C

$0.2$

D

$3.8$

Solution

Using $v=u+a t$

$\Rightarrow 20=u+a \times 10 \ldots(i)$

and $s_{n}=u+\frac{a}{2}(2 n-1)$

$\Rightarrow 10=u+\frac{a}{2}(2 \times 10-1)$ $…(ii)$

On solving $(i)$ and $(ii)$ we get $a=20 \mathrm{m} / \mathrm{s}^{2}$

Standard 11

Physics

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