An object accelerates from rest to a velocity | vedclass

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(c) $u = 0$, $v = 27.5\;m/s$ and $t = 10 \,sec$

$	herefore a = \frac{{27.5 - 0}}{{10}} = 2.75\;m/{s^2}$

Now, the distance traveled in next $10\

Vedclass · Accepted Answer

$412.5 $

Vedclass · Answer

(c) $u = 0$, $v = 27.5\;m/s$ and $t = 10 \,sec$

$	herefore a = \frac{{27.5 - 0}}{{10}} = 2.75\;m/{s^2}$

Now, the distance traveled in next $10\, sec$,

$S = ut + \frac{1}{2}a{t^2}$$ = 27.5 	imes 10 + \frac{1}{2} 	imes 2.75 	imes 100$

$= 275 + 137.5 = 412.5 \,m$

An object accelerates from rest to a velocity $27.5 \,m/s$ in $10 \,sec$ then find distance covered by object in next $10\, sec$........$m$

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