A particle is moving along a straight line with increasing speed. Its angular momentum about a fixed point on this line
Goes on increasing
Goes on decreasing
May be increasing or decreasing depending on direction of motion
Remains zero
Why the angular momentum perpendicular to the axis ${L_ \bot }$ in a rotational motion about a fixed axis ?
The position of a particle is given by : $\overrightarrow {r\,} = (\hat i + 2\hat j - \hat k)$ and momentum $\overrightarrow P = (3\hat i + 4\hat j - 2\hat k)$. The angular momentum is perpendicular to
Given $V _{ CM }=2\; m / s , m =2\; kg , R =4\; m $
Find angular momentum of ring about origin if it is in pure rolling. $kgm ^{2} / s$
A solid cylinder of mass $2\ kg$ and radius $0.2\,m$ is rotating about its own axis without friction with angular velocity $3\,rad/s$. A particle of mass $0.5\ kg$ and moving with a velocity $5\ m/s$ strikes the cylinder and sticks to it as shown in figure. The angular momentum of the cylinder before collision will be ........ $J-s$
Obtain the relation between torque of a system of particles and angular moment.