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2.Motion in Straight Line
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A particle is moving in a straight line such that its velocity is increasing at $5\,ms ^{-1}$ per meter. The acceleration of the particle is .......... $ms ^{-2}$ at a point where its velocity is $20\,ms ^{-1}$.
A$100$
B$101$
C$99$
D$103$
(JEE MAIN-2022)
Solution
$\frac{d v}{d s}=5$
$a=v \frac{d v}{d s}=20 \times 5=100\,m / sec ^{2}$
$a=v \frac{d v}{d s}=20 \times 5=100\,m / sec ^{2}$
Standard 11
Physics
Similar Questions
For the velocity-time graph shown in the figure, in a time interval from $t=0$ to $t=6\,s$, match the following columns.
Colum $I$ | Colum $II$ |
$(A)$ Change in velocity | $(p)$ $-5 / 3\,Sl$ unit |
$(B)$ Average acceleration | $(q)$ $-20\,SI$ unit |
$(C)$ Total displacement | $(r)$ $-10\,SI$ unit |
$(D)$ Acceleration at $t=3\,s$ | $(s)$ $-5\,SI$ unit |
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