A particle is moving in a straight line such that its velocity is increasing at $5\,ms ^{-1}$ per meter. The acceleration of the particle is $ms ^{-2}$ at a point where its velocity is $20\,ms ^{-1}$.
A particle is moving in a straight line such that its velocity is increasing at $5\,ms ^{-1}$ per meter. The acceleration of the particle is $ms ^{-2}$ at a point where its velocity is $20\,ms ^{-1}$.
- [JEE MAIN 2022]
- A
$100$
- B
$101$
- C
$99$
- D
$103$
Similar Questions
What is stopping distance ?
If the velocity of a body related to displacement ${x}$ is given by $v=\sqrt{5000+24 {x}} \;{m} / {s}$, then the acceleration of the body is $\ldots \ldots {m} / {s}^{2}$
If the velocity of a body related to displacement ${x}$ is given by $v=\sqrt{5000+24 {x}} \;{m} / {s}$, then the acceleration of the body is $\ldots \ldots {m} / {s}^{2}$
- [JEE MAIN 2021]
Speed-time graph of two cars $A$ and $B$ approaching towards each other is shown in figure. Initial distance between them is $60\,m$. The two cars will cross each other after time $..........\,s$
A car moving along a straight highway with speed of $126 \;\mathrm{km} h^{-1}$ is brought to a stop within a distance of $200\; \mathrm{m}$. What is the retardation of the car (assumed uniform in $m/s^2$) ?
A car moving along a straight highway with speed of $126 \;\mathrm{km} h^{-1}$ is brought to a stop within a distance of $200\; \mathrm{m}$. What is the retardation of the car (assumed uniform in $m/s^2$) ?
An automobile travelling with a speed of $60\,\,km/h,$ can brake to stop within a distance of $20 \,m$. If the car is going twice as fast, i.e. $120\, km/h$, the stopping distance will be ........... $m$
- [AIEEE 2004]