For the velocity-time graph shown in the figure, in a time interval from $t=0$ to $t=6\,s$, match the following columns.
Colum $I$ | Colum $II$ |
$(A)$ Change in velocity | $(p)$ $-5 / 3\,Sl$ unit |
$(B)$ Average acceleration | $(q)$ $-20\,SI$ unit |
$(C)$ Total displacement | $(r)$ $-10\,SI$ unit |
$(D)$ Acceleration at $t=3\,s$ | $(s)$ $-5\,SI$ unit |
$(A \rightarrow r, B \rightarrow p, C \rightarrow r, D \rightarrow s)$
$(A \rightarrow p, B \rightarrow r, C \rightarrow r, D \rightarrow s)$
$(A \rightarrow r, B \rightarrow r, C \rightarrow p, D \rightarrow s)$
$(A \rightarrow p, B \rightarrow p, C \rightarrow r, D \rightarrow s)$
A motorist starting a car from rest accelerates uniformly to a speed of $v\, m/s$ in $9\, seconds$. He maintains this speed for another $50\, seconds$ and then applies the brakes and decelerates uniformly to rest. His deceleration is numberically equal to three times his previous acceleration. Then the time during which the deceleration takes place is ..........$s$ :-
A small block slides without friction down an inclined plane starting from rest. Let ${S_n}$be the distance travelled from time $t = n - 1$ to $t = n.$ Then $\frac{{{S_n}}}{{{S_{n + 1}}}}$ is
A particle moves in a straight line so that its displacement $x$ at any time $t$ is given by $x^2=1+t^2$. Its acceleration at any time $\mathrm{t}$ is $\mathrm{x}^{-\mathrm{n}}$ where $\mathrm{n}=$ . . . . .
A particle moves towards east with velocity $5\, m/s$. After $10$ seconds its direction changes towards north with same velocity. The average acceleration of the particle is
A body starts from rest from the origin with an acceleration of $6\,m/{s^2}$ along the $x-$axis and $8\,m/{s^2}$ along the $y-$axis. Its distance from the origin after $4 \,seconds$ will be........$m$