A particle is moving on a circular path of radius $r$ with uniform speed $v$. The magnitude of change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^o)$
$2v\, cos\, 40^o$
$2v\, sin\, 40^o$
$2v\, sin\, 20^o$
$2v\, cos\, 20^o$
In uniform circular motion, the velocity vector and acceleration vector are
$Assertion$ : When a particle moves in a circle with a uniform speed, its velocity and acceleration both changes.
$Reason$ : The centripetal acceleration in circular motion is dependent on angular velocity of the body.
A particle is moving on a circular path with constant speed $v$. It moves between two points $A$ and $B$. which subtends an angle $60^{\circ}$ at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from $A$ to $B$ are respectively ..........
A particle is released on a vertical smooth semicircular track from point $X$ so that $OX$ makes angle $\theta $ from the vertical ( see figure). The normal reaction of the track on the particle vanishes at point $Y$ where $OY$ makes angle $\phi $ with the horizontal. Then
The linear speed of the tip of seconds hand of a wall clock is $1.05\,cm\,s^{-1}.$ The length of the seconds hand is nearly ........ $cm$