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3-2.Motion in Plane
medium
A particle is moving along a circular path with a constant speed of $10\,ms^{-1}.$ What is the magnitude of the change in velocity of the particle, when it moves through an angle of $60^{o}$ around the centre of the circle .......... $m/s$
A$10\sqrt 3 $
B$0$
C$10\sqrt 2 $
D$10$
(JEE MAIN-2019)
Solution
$\begin{array}{l}
\Delta \vec v\, = 2v\,\sin \left( {\frac{\theta }{2}} \right)\\
\,\,\,\,\,\,\, = 2 \times 10 \times \sin \left( {{{30}^ \circ }} \right)\\
\,\,\,\,\,\,\, = 10\,m/s
\end{array}$
\Delta \vec v\, = 2v\,\sin \left( {\frac{\theta }{2}} \right)\\
\,\,\,\,\,\,\, = 2 \times 10 \times \sin \left( {{{30}^ \circ }} \right)\\
\,\,\,\,\,\,\, = 10\,m/s
\end{array}$
Standard 11
Physics
