A particle is moving along a circular path with a constant speed of $10\,ms^{-1}.$ What is the magnitude of the change in velocity of the particle, when it moves through an angle of $60^{o}$ around the centre of the circle .......... $m/s$

  • [JEE MAIN 2019]
  • A
    $10\sqrt 3 $
  • B
    $0$
  • C
    $10\sqrt 2 $
  • D
    $10$

Similar Questions

Derive equation of motion of body moving in two dimensions

$\overrightarrow v \, = \,\overrightarrow {{v_0}} \, + \overrightarrow a t$ and $\overrightarrow r \, = \,\overrightarrow {{r_0}} \, + \overrightarrow {{v_0}} t\, + \,\frac{1}{2}g{t^2}$.

A boy walks uniformally along the sides of a rectangular park of size $400\, m × 300\, m$, starting from one corner to the other corner diagonally opposite. Which of the following statement is incorrect

A ball is dropped from a height and falls due to gravity and wind simultaneously imparts it a uniform horizontal acceleration. Which one of the following figures best represents its path?

If the position vector of a particle is

$\vec r =  - \cos \,t\hat i + \sin \,t\hat j - 18\,t\hat k$

then what is the magnitude of its acceleration ?

The position vector of an object at any time $t$ is given by $3 t^2 \hat{i}+6 t \hat{j}+\hat{k}$. Its velocity along $y$-axis has the magnitude