If the time of flight of a bullet over a hori | vedclass

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Question

(a)

$T=\frac{2 u \sin 	heta}{g} \Rightarrow u=\frac{g T}{2 \sin 	heta}$

$R=\frac{2 u^2 \sin 	heta \cos 	heta}{g}$

$R=\frac{2 u \sin 	het

Vedclass · Accepted Answer

$	an ^{-1}\left(\frac{g T^2}{2 R}ight)$

Vedclass · Answer

(a)

$T=\frac{2 u \sin 	heta}{g} \Rightarrow u=\frac{g T}{2 \sin 	heta}$

$R=\frac{2 u^2 \sin 	heta \cos 	heta}{g}$

$R=\frac{2 u \sin 	heta}{g} 	imes u \cos 	heta$

$R=T 	imes u \cos 	heta$

$R=T 	imes \frac{g T \cos 	heta}{2 \sin 	heta}$

$R=\frac{g T^2}{2} \frac{1}{	an 	heta}$

$	an 	heta=\frac{g T^2}{2 R}$

$	heta=	an ^{-1}\left(\frac{g T^2}{2 R}ight)$

If the time of flight of a bullet over a horizontal range $R$ is $T$, then the angle of projection with horizontal is ......

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