A stone is projected from ground at t = 0. At | vedclass

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Question

at any instant

$a_{t}=g \sin 	heta$

$a_{n}=g \cos 	heta$

$\because a_{n}=a_{r}$

$\Rightarrow 	an 	heta=1 \Rightarrow\left|\frac{v_{y}}

Vedclass · Accepted Answer

$3$

Vedclass · Answer

at any instant

$a_{t}=g \sin 	heta$

$a_{n}=g \cos 	heta$

$\because a_{n}=a_{r}$

$\Rightarrow 	an 	heta=1 \Rightarrow\left|\frac{v_{y}}{v_{x}}ight|=1$

$\Rightarrow \frac{\mathrm{v}_{\mathrm{y}}}{\mathrm{v}_{\mathrm{x}}}=\pm 1 \Rightarrow \frac{\mathrm{u}_{\mathrm{y}}-\mathrm{gt}}{\mathrm{u}_{\mathrm{x}}}=\pm 1$

Solving we get

$t=1$ and $3$

A stone is projected from ground at $t = 0$. At the time of projection horizontal and vertical component of velocity are $10\, m/s$ and $20\, m/s$ respectively. Then time at which tangential and normal acceleration magnitude will be equal $(g = 10\, m/s^2)$ [neglect air friction] ......... $\sec$

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