A particle is projected upwards. times corresponding to height h while ascending and while descendin

English

Gujarati

Hindi

2.Motion in Straight Line

medium

A particle is projected upwards. The times corresponding to height $h$ while ascending and while descending are $t‌‌_1$ and $t_2$ respectively. The velocity of projection will be

A

$g{t_1}$

B

$g{t_2}$

C

$g\;\left( {{t_1} + {t_2}} \right)$

D

$\frac{{g\left( {{t_1} + {t_2}} \right)}}{2}$

Solution

(d) If ${t_1}$ and ${t_2}$ are time of ascent and descent respectively then time of flight $T = {t_1} + {t_2} = \frac{{2u}}{g}$

==> $u = \frac{{g({t_1} + {t_2})}}{2}$

Standard 11

Physics

Share

Similar Questions

Water drops fall at regular intervals from a tap which is $5\,\,m$ above the ground. The third drop is leaving the tap at the instant the first drop touches the ground. How far above the ground is the second drop at that instant………$m$

hard

(AIPMT-1995)

A man is standing on top of a building $100\, m$ high. He throws two balls vertically, one at $t = 0$ and after a time interval (less than $2\,\sec $). The later ball is thrown at a velocity of half the first. The vertical gap between first and second ball is $+15\, m$ at $t = 2\,\sec $. The gap is found to remain constant. Calculate the velocity with which the balls were thrown and the exact time interval between their throw.

hard

From a tower of height $H$, a particle is thrown vertically upwards with a speed $ u$. The time taken by the particle, to hit the ground, is $n$ times that taken by it to reach the highest point of its path. The relation between $H, u$ and $n$ is:

hard

(JEE MAIN-2014)

A body is thrown vertically upwards with a velocity of $19.6\, ms^{-1}$. The position of the body after $4\, s $ will be

easy

(AIIMS-2009)

If a particle takes $t$ second less and acquires a velocity of $v \ ms^{^{-1}}$ more in falling through the same distance (starting from rest) on two planets where the accelerations due to gravity are $2 \,\, g$ and $8 \,\,g$ respectively then $v=$

hard