A particle is projected with velocity ${\upsilon _0}$ along $x - axis$. The deceleration on the particle is proportional to the square of the distance from the origin i.e., $a = \alpha {x^2}.$ The distance at which the particle stops is
- A$\sqrt {\frac{{3{\upsilon _0}}}{{2\alpha }}} $
- B${\left( {\frac{{3{v_o}}}{{2\alpha }}} \right)^{\frac{1}{3}}}$
- C$\sqrt {\frac{{3\upsilon {}_0^2}}{{2\alpha }}} $
- D${\left( {\frac{{3\upsilon {}_0^2}}{{2\alpha }}} \right)^{\frac{1}{3}}}$
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