Angle turned by a body undergoing circular motion depends on time as θ = {θ _0} + {θ ₁}t + {θ

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3-2.Motion in Plane

easy

The angle turned by a body undergoing circular motion depends on time as $\theta = {\theta _0} + {\theta _1}t + {\theta _2}{t^2}$. Then the angular acceleration of the body is

A${\theta _1}$

B${\theta _2}$

C$2{\theta _1}$

D$2{\theta _2}$

Solution

(d)Angular acceleration$ = \frac{{{d^2}\theta }}{{d{t^2}}}= 2\theta_2$

Standard 11

Physics

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