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3-2.Motion in Plane
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A particle is thrown with a speed $u$ at an angle $\theta$ with the horizontal. When the particle makes an angle $\phi$ with the horizontal, its speed changes to $v$, where
A$v=u \cos \theta$
B$v=u \cos \theta \cos \phi$
C$v=u \cos \theta \sec \phi$
D$v=u \sec \theta \cos \phi$
Solution
(c)
Horizontal component of velocity remains unchanged. Hence,
$v \cos \phi=u \cos \theta$
$\therefore \quad v=u \cos \theta \sec \phi$
Horizontal component of velocity remains unchanged. Hence,
$v \cos \phi=u \cos \theta$
$\therefore \quad v=u \cos \theta \sec \phi$
Standard 11
Physics
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