A projectile is thrown upward with a velocity v_0 at an angle α to horizontal. change in velocity o

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3-2.Motion in Plane

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A projectile is thrown upward with a velocity $v_0$ at an angle $\alpha$ to the horizontal. The change in velocity of the projectile when it strikes the same horizontal plane is

A

$v_0 \sin \alpha$ vertically downwards

B

$2 v_0 \sin \alpha$ vertically downwards

C

$2 v_0 \sin \alpha$ vertically upwards

D

zero

Solution

(b)

$\Delta a = a \Delta t( a s$ a $=$ constant $)$

$=(-g \hat{ j })\left(\frac{2 v_0 \sin \alpha}{g}\right)=\left(-2 v_0 \alpha\right) \hat{ j }$

i.e. change in velocity is $2 v_0 \sin \alpha$, vertically downwards.

Standard 11

Physics

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