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3-2.Motion in Plane
medium
A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $m/{s^2}$ is
A${\pi ^2}$
B$8{\pi ^2}$
C$4{\pi ^2}$
D$2{\pi ^2}$
Solution
(c) Since $n = 2$, $\omega = 2\pi \times 2 = 4\pi \,rad/{s^2}$
So acceleration $ = {\omega ^2}r$ $ = {(4\pi )^2} \times \frac{{25}}{{100}}\,m/{s^2} = 4{\pi ^2}$
So acceleration $ = {\omega ^2}r$ $ = {(4\pi )^2} \times \frac{{25}}{{100}}\,m/{s^2} = 4{\pi ^2}$
Standard 11
Physics
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