A particle moves in a circle of radius 25, cm | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) Since $n = 2$, $\omega = 2\pi 	imes 2 = 4\pi \,rad/{s^2}$

So acceleration $ = {\omega ^2}r$ $ = {(4\pi )^2} 	imes \frac{{25}}{{100}}\,m/{s^2}

Vedclass · Accepted Answer

$4{\pi ^2}$

Vedclass · Answer

(c) Since $n = 2$, $\omega = 2\pi 	imes 2 = 4\pi \,rad/{s^2}$

So acceleration $ = {\omega ^2}r$ $ = {(4\pi )^2} 	imes \frac{{25}}{{100}}\,m/{s^2} = 4{\pi ^2}$

A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $m/{s^2}$ is

Similar Questions

car moves on a circular road. It describes equal angles about the centre in equal intervals of time. Which of the following statement about the velocity of the car is true

A ball is moving uniformly in a circular path of radius $1 m$ with a time period of $1.5 \,s$. If the ball is suddenly stopped at $t=8.3 \,s$, the magnitude of the displacement of the ball with respect to its position at $t=0 \,s$ is closest to .......... $m$

A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector $\vec a$ is correctly shown in

A body performing unifom circular motion completed $140$ revolution in a second. Its angular speed is .......... $rad / s$

In uniform circular motion