Gujarati
Hindi
5.Work, Energy, Power and Collision
normal

A particle of mass $M$ starting from rest undergoes uniform acceleration. If the speed acquired in time $T$ is $V$, then power delivered to the particle in time $T$ is

A

$\frac{1}{2}\,\frac{{M{V^2}}}{{{T^2}}}$

B

$\frac{{M{V^2}}}{{{T^2}}}$

C

$\frac{1}{2}\,\frac{{M{V^2}}}{T}$

D

$\frac{{M{V^2}}}{T}$

Solution

$P_{\text {avg }}=\frac{W}{\Delta t}=\frac{\frac{1}{2} M V^{2}-0}{T}=\frac{1}{2} \frac{M V^{2}}{T}$

Standard 11
Physics

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