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5.Work, Energy, Power and Collision
normal
A vertical spring with force constant $k$ is fixed on a table. A ball of mass $m$ at a height $h$ above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance $d$. The net work done in the process is
A
$mg\left( {h + d} \right) - \frac{1}{2}\,k{d^2}$
B
$mg\left( {h - d} \right) - \frac{1}{2}\,k{d^2}$
C
$mg\left( {h - d} \right) + \frac{1}{2}\,k{d^2}$
D
$mg\left( {h + d} \right) + \frac{1}{2}\,k{d^2}$
Solution
Gravitational potential energy of ball gets converted into elastic potential energy of the spring.
$mg (h+d) = \frac{1}{2}k{d^2}$
Net work done $= mg\, (h+d)$ $ – \frac{1}{2}k{d^2} = 0$
Standard 11
Physics
