Force F acting on a body moving in a circle of radius r is always perpendicular to the&nb

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5.Work, Energy, Power and Collision

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The force $F$ acting on a body moving in a circle of radius $r$ is always perpendicular to the instantaneous velocity $v$. The work done by the force on the body in one complete rotation is :

A

$Fv$

B

$F.2 \pi r$

C

$Fr$

D

$0$

Solution

Work $=F . d \cos \theta ;$ as $\theta=90^{\circ}$

$\Rightarrow$ work $=0$

Standard 11

Physics

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