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5.Work, Energy, Power and Collision
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The force $F$ acting on a body moving in a circle of radius $r$ is always perpendicular to the instantaneous velocity $v$. The work done by the force on the body in one complete rotation is :
A
$Fv$
B
$F.2 \pi r$
C
$Fr$
D
$0$
Solution
Work $=F . d \cos \theta ;$ as $\theta=90^{\circ}$
$\Rightarrow$ work $=0$
Standard 11
Physics
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