A particle of mass $m$ moving with velocity $V_0$ strikes a simple pendulum of mass $m$ and sticks to it. The maximum height attained by the pendulum will be

  • A

    $h = \frac{{V_0^2}}{{8g}}$

  • B

    $\sqrt {{V_0}g} $

  • C

    $2\sqrt {\frac{{{V_0}}}{g}} $

  • D

    $\frac{{V_0^2}}{{4g}}$

Similar Questions

If the momentum of a body increases by $0.01\%$, its kinetic energy will increase by ........... $\%$

A bullet of mass $m$ moving with velocity $v$ strikes a block of mass $M$ at rest and gets embedded into it. The kinetic energy of the composite block will be

A sphere of mass $m$ travelling at constant speed $v$ strike another sphere of same mass. If  coefficient of restitution is $e$, then ratio of velocity of both spheres just after collision is :-

A neutron makes a head-on elastic collision with a stationary deuteron. The fractional energy loss of the neutron in the collision is

System shown in figure is released from rest. Pulley and spring are massless and the friction is absent everywhere. The speed of $5\, kg$ block, when $2\, kg$ block leaves the contact with ground is : (take force constant of the spring $K = 40\, N/m$ and $g = 10\, m/s^2$)