- Home
- Standard 11
- Physics
4-1.Newton's Laws of Motion
hard
સ્થિર સ્થિતિમાં રહેલા $m$ દળના કણ પર લાગતા બળનો આલેખ આપેલ છે.બળ બંધ થયા પછી તેનો વેગ $u$ હોય તો $u$ કેટલો થાય?
A
$u = \frac{{\pi F_0^2}}{{2m}}$
B
$u = \frac{{\pi {T^2}}}{{8m}}$
C
$u = \frac{{\pi {F_0}T}}{{4m}}$
D
$u = \frac{{{F_0}T}}{{2m}}$
Solution
(c) Initially particle was at rest. By the application of force its momentum increases. Final momentum of the particle $ = $ Area of $F – t$ graph
$⇒$ $mu = $ Area of semi circle
$mu = \frac{{\pi \;{r^2}}}{2}$
$ = \frac{{\pi \;{r_1}{r_2}}}{2}$
$ = \frac{{\pi \;({F_0})\;(T/2)}}{2}$
$⇒$ $u = \frac{{\pi \;{F_0}T}}{{4m}}$
Standard 11
Physics
