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1. Electric Charges and Fields
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A particle of mass $\mathrm{m}$ and charge $\mathrm{q}$ is released from rest in a uniform electric field. If there is no other force on the particle, the dependence of its speed $v$ on the distance $x$ travelled by it is correctly given by (graphs are schematic and not drawn to scale)
A

B

C

D

(JEE MAIN-2020)
Solution

$\mathrm{v}^{2}=\mathrm{u}^{2}+2 \mathrm{as}$
$\mathrm{v}^{2}=0+2\left(\frac{\mathrm{qE}}{\mathrm{m}}\right) \mathrm{x}$
$\mathrm{v}^{2}=\frac{2 \mathrm{q} \mathrm{E}}{\mathrm{m}} \mathrm{x}$
Standard 12
Physics
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