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4.Moving Charges and Magnetism
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A particle of mass $0.6\, g$ and having charge of $25\, nC$ is moving horizontally with a uniform velocity ${\rm{1}}{\rm{.2}} \times {\rm{1}}{{\rm{0}}^{\rm{4}}}\,m{s^{ - 1}}$ in a uniform magnetic field, then the value of the magnetic induction is $(g = 10\,m{s^{ - 2}})$
A
Zero
B
$10\, T$
C
$20\, T$
D
$200\, T$
Solution

(c) Particle will move with uniform velocity when it’s acceleration is zero.
i.e. $|{F_m}|\, = \,mg \Rightarrow mg = qvB$
$ \Rightarrow B = \frac{{mg}}{{qv}} = \frac{{0.6 \times {{10}^{ – 3}} \times 10}}{{25 \times {{10}^{ – 9}} \times 1.2 \times {{10}^4}}} = 20\,T$
Standard 12
Physics
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