A particle of mass $m$ and charge $q$ is kept at the top of a fixed frictionless sphere. $A$ uniform horizontal electric field $E$ is switched on. The particle looses contact with the sphere, when the line joining the center of the sphere and the particle makes an angle $45^o$ with the vertical. The ratio $\frac{qE}{mg}$ is :-

  • A

    $\frac{3}{{3 + 2\sqrt 2 }}$

  • B

    $\frac{{3 + 2\sqrt 2 }}{3}$

  • C

    $\frac{3}{{3 - 2\sqrt 2 }}$

  • D

    $\frac{{3 - 2\sqrt 2 }}{3}$

Similar Questions

If $4 \times {10^{20}}eV$ energy is required to move a charge of $0.25$ coulomb between two points. Then what will be the potential difference between them......$V$

Prove that electrostatic forces are conservative in nature and define electrostatic potential energy.

Two positrons $(e^+)$ and two protons $(p)$ are kept on four corners of a square of side $a$ as shown in figure. The mass of proton is much larger than the mass of positron. Let $q$ denotes the charge on the proton as well as the positron then the kinetic energies of one of the positrons and one of the protons respectively after a very long time will be-

Three charges are placed along $x$-axis at $x=-a, x=0$ and $x=a$ as shown in the figure. The potential energy of the system is

Kinetic energy of an electron accelerated in a potential difference of $100\, V$ is